Rs Aggarwal 2021 2022 Solutions for Class 9 Maths Chapter 16 Presentation Of Data In Tabular Form are provided here with simple step-by-step explanations. These solutions for Presentation Of Data In Tabular Form are extremely popular among Class 9 students for Maths Presentation Of Data In Tabular Form Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2021 2022 Book of Class 9 Maths Chapter 16 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2021 2022 Solutions. All Rs Aggarwal 2021 2022 Solutions for class Class 9 Maths are prepared by experts and are 100% accurate.

Page No 623:

Answer:

Statistics is the science which deals with the collection, presentation, analysis and interpretation of numerical data.

Page No 623:

Answer:

The fundamental characteristics of data (statistics) are as follows:
(i) Numerical facts alone constitute data.
(ii) Qualitative characteristics like intelligence and poverty, which cannot be measured numerically, do not form data.
(iii) Data are aggregate of facts. A single observation does not form data.
(iv) Data collected for a definite purpose may not be suited for another purpose.
(v) Data in different experiments are comparable.

Page No 623:

Answer:

Primary data: The data collected by the investigator himself with a definite plan in mind are known as primary data.
Secondary data: The data collected by someone other than the investigator are known as secondary data.

Primary data are highly reliable and relevant because they are collected by the investigator himself with a definite plan in mind,  whereas secondary data are collected with a purpose different from that of the investigator and may not be fully relevant to the investigation.

Page No 623:

Answer:

(i) Variate : Any character which is capable of taking several different values is called a variant or a variable.
(ii) Class interval : Each group into which the raw data is condensed is called class interval .
(iii) Class size: The difference between the true upper limit and the true lower limit of a class is called its class size.
(iv) Class mark of a class: The class mark is given by Upper limit+Lower limit2.
(v) Class limit: Each class is bounded by two figures, which are called class limits.
(vi) True class limits: In the exclusive form, the upper and lower limits of a class are respectively known as true upper limit and true lower limit.
In the inclusive form of frequency distribution, the true lower limit of a class is obtained by subtracting 0.5 from the lower limit and the true upper limit of the class is obtained by adding 0.5 to the upper limit.
(vii) Frequency of a class: Frequency of a class is the number of times an observation occurs in that class.
(viii) Cumulative frequency of a class: Cummulative frequency of a class is the sum total of all the frequencies up to and including that class.



Page No 624:

Answer:

(i) 

Blood group tally marks Number of students
A 9
B 6
O 12
AB 3

(ii) AB is rarest and O is most common. 

Page No 624:

Answer:

Number of heads tally marks Frequency
0 6
1 10
2 9
3 5

Page No 624:

Answer:

The minimum observation is 0 and the maximum observation is 8.
Therefore, classes of  the same size covering the given data are 0-2, 2-4, 4-6 and 6-8.          .


Frequency distribution table:
        Class               Tally mark          Frequency
        0-2            11
        2-4            17
        4-6             9
        6-8             3

Page No 624:

Answer:

(i) 

Class interval tally marks Frequency
0-5 10
5-10 13
10-15 5
15-20 2

(ii) As we can see from the table, there are 2 children who watched tv for 15 hours or more. 

Page No 624:

Answer:

The minimum observation is 0 and the maximum observation is 25.
Therefore, classes of the same size covering the given data are 0-5, 5-10, 10-15, 15-20 and 20-25.
Frequency distribution table:

                 Class Tally mark Frequency
                  0-5         6
                5-10       10
               10-15         8
               15-20         8
               20-25         8

Page No 624:

Answer:

The minimum observation is 6 and the maximum observation is 24.
Therefore, classes of the same size covering the given data are 6-9, 9-12, 12-15, 15-18, 18-21 and 21-24.
Frequency distribution table:
         Class            Tally mark          Frequency
          6-9                             5
         9-12                              4
       12-15                              4
       15-18                              7
       18-21                              3
       21-24                              7

Page No 624:

Answer:

The minimum observation is 210 and the maximum observation is 330.
Therefore, classes of the same size covering the given data are 210-230, 230-250,250-270,270-290,290-310 and 310-330.
Frequency distribution table:
 

            Class        Tally mark           Frequency
           210-230                            4
           230-250                            4
          250-270                           5
          270-290                             3
          290-310                           7
          310-330                           5



Page No 625:

Answer:

The minimum observation is 30 and the maximum observation is 120.
                                                
Frequency distribution table:

           Class                 Tally mark            Frequency
30-40                                     4
40-50                                    6
50-60                                     3
60-70                                    5
70-80                                    9
80-90                                     6
90-100                                       2
100-110                                     3
110-120                                      2

                                     
Cumulative frequency table:

   Class    Tally mark    Frequency      Cumulative frequency
30-40                     4                   4
40-50                    6                  10
50-60                     3                  13
60-70                    5                  18
70-80                9                  27
80-90                  6                  33
90-100                     2                  35
100-110                    3                  38
110-120                     2                  40

Page No 625:

Answer:

Class tally marks Frequency Cumulative frequency
145-150 4 4
150-155 9 4 + 9 = 13
155-160 12 13 + 12 = 25
160-165 5 25 + 5 = 30

Page No 625:

Answer:

The cumulative frequency table can be presented as given below:
 

      Age (in years ) No. of patients      Cumulative frequency
          10-20 90                 90         
          20-30 50        140
          30-40 60         200
          40-50 80         280
          50-60 50         330
          60-70 30         360

Page No 625:

Answer:

The grouped frequency table can be presented as given below:
 

            Marks         No. of students
              0-10                      5
            10-20                      7
            20-30                    20
            30-40                     8
            40-50                     5
            50-60                     3

Page No 625:

Answer:

The frequency table can be presented as given below:
 

             Marks   Number of students
              0-10                   17
             10-20                    5
             20-30                    7
             30-40                    8
             40-50                  13
             50-60                  10

Page No 625:

Answer:

The frequency table can be presented as below:
 

            Class     Frequency
               0-10            8
              10-20            5
               20-30          12
               30-40          35
               40-50          24
               50-60          16



Page No 626:

Answer:

Range = Maximum value - minimu value
= 100 - 46 = 54
Thus, the range is 54.

Page No 626:

Answer:

(i) class mark=upper limit+lower limit2=120+902=2102=105
(ii) mid-value = 10
width = 6
Let the lower limit of the class be x
upper limit = x + 6
class mark/mid-value=upper limit+lower limit2
x+x+62=10x=7
(iii) width = 5
lower class limit of lowest class = 10
The classes will be 10-15, 15-20, 20-25, 25-30, 30-35.
Upper class limit of the highest class = 35.
(iv) Class marks = 15, 20, 25, ...
class size = 20 - 15 = 5
Let lower limit of class be x.
x+x+52=20x=17.5
Thus, the class is 17.5-22.5. 
(v) 20 will be included in the class interval 20-30. 

Page No 626:

Answer:

The  complete table will be

Height (in cm) Frequency Cumulative frequency
160 – 165 15 a = 15
165 – 170 b = 35 – 15 = 20  35
170 – 175 12 = 35 + 12 = 47
175 – 180 d = 50 – 47 = 3 50
180 – 185 e = 55 – 50 = 5 55
185 –  190 5 f = 55 + 5 = 60
  g = 15 + 20 + 12
+ 3 + 5 + 5 = 60
 

 



Page No 628:

Answer:

(d) 26

We have:
Maximum value = 32
Minimum value = 6
We know:
Range = Maximum value - Minimum value 
          =32 - 6
          =26

Page No 628:

Answer:

(b) 110

Class mark = Upper limit+Lower limit2=120+1002=110



Page No 629:

Answer:

(b) 2030
This is the continuous form of frequency distribution. Here, the upper limit of each class is excluded, while the lower limit is included. So, the number 20 is included in the class interval 2030.

Page No 629:

Answer:

(b) 17.5-22.5

We are given frequency distribution 15, 20, 25, 30,...
Class size = 20 - 15 = 5
Class marks = 20
Now,
Lower limit=20-52=352=17.5Upper limit =20+52=452=22.5

Thus, the required class is 17.5-22.5.

Page No 629:

Answer:

(b) 7

Given:
Mid value of the class = 10
Width of each class = 6
Now,
Let the lower limit be x.
We know:
Upper limit = Lower limit + Class size
                  = x + 6
Also,
Mid value=x+x+62=2x+62=x+3x+3=10x=7

Thus, the lower limit is 7.

Page No 629:

Answer:

(a) 37–47

Let the lower limit be x.
Here,
Class size = 10
∴ Upper limit = Class size + Lower limit
Upper limit = (x + 10)
Mid value of the class interval = 42

x+x+102=422x+102=422x+10=842x=74x=37Thus, we have:Lower limit=37 Upper limit=37+10=47

Page No 629:

Answer:

(a) 2m - u

Given:
Mid value = m
Upper limit = u

We know:
Lower limit+Upper limit2=Mid value Lower limit +u2=mLower limit+u=2mLower limit=2m-u

Page No 629:

Answer:

(c) 35

We have:
Class width = 5
Lower class limit of the lowest class = 10
Now,
Upper class limit of the highest class = 10 + 5 × 5 = 35

Page No 629:

Answer:

(c) 2m-L

Mid value=Lower limit+Upper limit2m=L+U2U=2m-LUpper class boundary of the class=2m-L



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