Rs Aggarwal 2020 2021 Solutions for Class 8 Maths Chapter 19 Three Dimensional Figures are provided here with simple step-by-step explanations. These solutions for Three Dimensional Figures are extremely popular among Class 8 students for Maths Three Dimensional Figures Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2020 2021 Book of Class 8 Maths Chapter 19 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2020 2021 Solutions. All Rs Aggarwal 2020 2021 Solutions for class Class 8 Maths are prepared by experts and are 100% accurate.

Page No 215:

Answer:

(i) A cuboid has 6 faces, namely ABCD, EFGH, HDAE, GCBF, HDCG and EABF.



(ii) A cube has 6 faces, namely IJKL, MNOP, PLIM, OKJN, LKOP and IJNM.


(iii) A triangular prism has 5 faces (3 rectangular faces and 2 triangular faces), namely  QRUT, QTVS, RUVS, QRS and TUV.


(iv) A square pyramid has 5 faces (4 triangular faces and 1 square face), namely OWZ, OWX, OXY, OYZ and WXYZ.


(v) A tetrahedron has 4 triangular faces, namely KLM, KLN, LMN and KMN.

Page No 215:

Answer:

(i) A tetrahedron has 6 edges, namely KL, LM, LN, MN, KN and KM.


(ii) A rectangular pyramid has 8 edges, namely AB, AE, AD, AC, EB, ED, DC and CB.


(iii)  A cube has 12 edges, namely PL, LK, KO, OP, MN, NJ, JI, IM, PM, LI, ON and KJ.


(iv) A triangular prism has 9 edges, namely QR, RS, QS, TU, TV, UV, QT, RU, and SV.

Page No 215:

Answer:

(i) A cuboid has 8 vertices, namely A, B, C, D, E, F, G and H.


(ii) A square pyramid has 5 vertices, namely O, W, X, Y and Z.


(iii)A tertrahedron has 4 vertices, namely K, L, M and N.


(iv) A triangular prism has 6 vertices, namely Q, R, S, T, U and V.

Page No 215:

Answer:

(i) A cube has 8 vertices, 12 edges and 6 faces.                   
Vertices: I, J, K, L, M, N, O and P
Edges : IJ, JN, NM, MI, PL, LK, KO, OP, PM, LI, KJ, and ON
Faces : MNJI, POKL, PLIM, OKJN, PONM and LKJI

(ii) The point at which the three faces of a figure meet is known as its vertex.
(iii) A cuboid is also known as a rectangular cube.
(iv) A triangular pyramid is called a tetrahedraon.



Page No 217:

Answer:

The Euler's relation for a three dimensional figure can be expressed in the following manner:

F-E+V=2Here,F- Number of facesE-Number of edgesV-Number of vertices

Page No 217:

Answer:

(i) A cuboid has 12 edges, namely AD, DC, CB, BA, EA, FB, HD, DC, CG, GH, HE, and GF.


(ii) A tetrahedron has 6 edges, namely KL, LM, MN, NL , KM and KN.

(iii) A triangular prism has 9 edges, namely QR, RS, SQ, TU, UV, VT, RU, SV and QT.


(iv) A square pyramid has 8 edges, namely OW, OX, OY , OZ , WX, XY, YZ and ZW.

Page No 217:

Answer:

(i) A cube has 6 faces, namely IJKL, MNOP, PLIM , OKJN, POKL and MNJI.


(ii) A pentagonal prism has 7 faces, i.e. 2 pentagons and 5 rectangles, namely ABCDE, FGHIJ, ABGF, AEJF , EDIJ, DCHI and CBGH.


(iii) A tetrahedron has 4 faces, namely KLM, KLN, LMN and KMN.


(iv) A pentagonal pyramid has 6 faces, i.e. 1 pentagon and 5 triangles, namely NOPQM, SNM, SOP, SNO, SMQ and  SQP.

Page No 217:

Answer:

(i) A cuboid has 8 vertices, namely A, B, C, D, E, F, G and H.


(ii) A tetrahedron has 4 vertices, namely K, L, M and N.


(iii) A pentagonal prism has 10 vertices, namely A, B, C, D, E, F, G, H, I and J.


(iv) A square pyramid has 5 vertices, namely O, W, X, Y and Z.

Page No 217:

Answer:

Euler's relation is:

F-E+V=2Here:F- Number of facesE-Number of edgesV-Number of vertices

(i) A square prism  

(There is an error in this question. It should have been a square prism rather than square.)                                        

Number of faces = F=2 squares+4 rectangular=6Number of edges = E = 12Number of vertices =V= 8F-E+V=6-12+8=2

(ii) A tetrahedron

Number of faces = F=4Number of edges = E = 6Number of vertices =V= 4F-E+V=4-6+4=2

(iii) A triangular prism

Number of faces = F=2 triangular + 3 rectangular = 5Number of edges = E = 9 Number of vertices =V =6F-E+V=5-9+6=2

(iv) A square pyramid

Number of faces = F=2 triangular + 3 rectangular = 5Number of edges = E = 8Number of vertices =V =5F-E+V=5-8+5=2



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