Rs Aggrawal 2019 2020 for Class 6 Math Chapter 6 - Simplification

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Rs Aggrawal 2019 2020 Solutions for Class 6 Math Chapter 6 Simplification are provided here with simple step-by-step explanations. These solutions for Simplification are extremely popular among Class 6 students for Math Simplification Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggrawal 2019 2020 Book of Class 6 Math Chapter 6 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggrawal 2019 2020 Solutions. All Rs Aggrawal 2019 2020 Solutions for class Class 6 Math are prepared by experts and are 100% accurate.

Page No 107:

Answer:

Given expression:
= 21 - 12 $\div$ 3 ⨯ 2
= 21 - 4 ⨯ 2 [Performing division]
= 21 - 8 [Performing multiplication]
= 13 [Performing subtraction]

Page No 107:

Answer:

Given expression:
= 16 + 8 $\div$ 4 - 2 ⨯ 3
= 16 + 2 - 2 ⨯ 3 [Performing division]
= 16 + 2 - 6 [Performing multiplication]
= 18 - 6 [Performing addition]
= 12 [Performing subtraction]

Page No 107:

Answer:

Given expression:
= 13 - (12 - 6 ÷ 3 )
= 13 - (12 - 2) [Performing division]
= 13 - 10 = 3 [Performing subtraction]

Page No 107:

Answer:

Given expression:
= 19 - [4 + {16 - (12 - 2)}]
= 19 - [4 + {16 - 10}] [Removing parentheses]
= 19 - [4 + 6] [Removing braces]
= 19 - 10 [Removing square brackets]
= 9

Page No 107:

Answer:

Given expression:
= 36 - [18 - {14 - (15 - 4 ÷ 2 × 2)}]
= 36 - [18 - {14 - (15 - 2 × 2)}] [Performing division]
= 36 - [18 - {14 - (15 - 4)}] [Performing multiplication]
= 36 - [18 - {14 - 11}] [Removing parentheses]
= 36 - [18 - 3] [Removing braces]
= 36 - 15 [Removing square brackets]
= 21

Page No 107:

Answer:

Given expression:
= 27 - [18 - {16 - (5 - $4 - 1$ )}]
= 27 - [18 - {16 - (5 - 3)}]    [Removing bar]
= 27 - [18 - {16 - 2}]       [Removing parentheses]
= 27 - [18 - 14]       [Removing braces]
= 27 - 4    [Removing square brackets]
= 23

Page No 107:

Answer:

Given expression:
$= 4 \frac{4}{5} \div \frac{3}{5} of 5 + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} = 4 \frac{4}{5} \div \frac{3}{5} \times \frac{5}{1} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (Removing' of') = \frac{24}{5} \div \frac{3}{1} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} = \frac{24}{5} \times \frac{1}{3} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (Removing' \div') = \frac{8}{5} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (Removing' \times') = \frac{8}{5} + \frac{6}{25} - \frac{1}{5} (Removing' \times') = \frac{40 + 6 - 5}{25} = \frac{41}{25} = 1 \frac{16}{25}$

Page No 107:

Answer:

Given expression:
$= (\frac{2}{3} + \frac{4}{9}) of \frac{3}{5} \div 1 \frac{2}{3} \times 1 \frac{1}{4} - \frac{1}{3} = (\frac{6 + 4}{9}) of \frac{3}{5} \div 1 \frac{2}{3} \times 1 \frac{1}{4} - \frac{1}{3} (Removing parentheses) = \frac{10}{9} \times \frac{3}{5} \div 1 \frac{2}{3} \times 1 \frac{1}{4} - \frac{1}{3} (Removing' of') = \frac{2}{3} \div \frac{5}{3} \times 1 \frac{1}{4} - \frac{1}{3} = \frac{2}{3} \times \frac{3}{5} \times \frac{5}{4} - \frac{1}{3} (Removing' \div') = \frac{2}{5} \times \frac{5}{4} - \frac{1}{3} = \frac{1}{2} - \frac{1}{3} (Removing' \times') = \frac{(3 - 2)}{6} = \frac{1}{6}$

Page No 107:

Answer:

The given expression
$= 7 \frac{1}{3} \div \frac{2}{3} of 2 \frac{1}{5} + 1 \frac{3}{8} \div 2 \frac{3}{4} - 1 \frac{1}{2} = \frac{22}{3} \div \frac{2}{3} of \frac{11}{5} + \frac{11}{8} \div \frac{11}{4} - \frac{3}{2} = \frac{22}{3} \div \frac{2}{3} \times \frac{11}{5} + \frac{11}{8} \div \frac{11}{4} - \frac{3}{2} (Removing' of') = \frac{22}{3} \div \frac{22}{15} + \frac{11}{8} \div \frac{11}{4} - \frac{3}{2} = \frac{22}{3} \times \frac{15}{22} + \frac{11}{8} \div \frac{11}{4} - \frac{3}{2} (Removing' \div') = 5 + \frac{11}{8} \times \frac{4}{11} - \frac{3}{2} (Removing' \div') = 5 + \frac{1}{2} - \frac{3}{2} (On simplifying) = \frac{10 + 1 - 3}{2} = \frac{8}{2} = 4$

Page No 107:

Answer:

Given expression:
$= 5 \frac{1}{7} - \{3 \frac{3}{10} \div (2 \frac{4}{5} - \frac{7}{10})\} = \frac{36}{7} - \{\frac{33}{10} \div (\frac{14}{5} - \frac{7}{10})\} = \frac{36}{7} - \{\frac{33}{10} \div (\frac{28 - 7}{10})\} = \frac{36}{7} - \{\frac{33}{10} \div \frac{21}{10}\} (Removing parentheses) = \frac{36}{7} - \{\frac{33}{10} \times \frac{10}{21}\} (Removing' \div') = \frac{36}{7} - \frac{11}{7} (Removing braces) = \frac{36 - 11}{7} = \frac{25}{7} = 3 \frac{4}{7} (Simplifying)$

Page No 107:

Answer:

Given expression:
$= 9 \frac{3}{4} \div [2 \frac{1}{6} + \{4 \frac{1}{3} - (1 \frac{1}{2} + 1 \frac{3}{4})\}] = \frac{39}{4} \div [\frac{13}{6} + \{\frac{13}{3} - (\frac{3}{2} + \frac{7}{4})\}] = \frac{39}{4} \div [\frac{13}{6} + \{\frac{13}{3} - (\frac{6 + 7}{4})\}] = \frac{39}{4} \div [\frac{13}{6} + \{\frac{13}{3} - \frac{13}{4}\}] (Removing parentheses) = \frac{39}{4} \div [\frac{13}{6} + \{\frac{52 - 39}{12}\}] = \frac{39}{4} \div [\frac{13}{6} + \frac{13}{12}] (Removing braces) = \frac{39}{4} \div [\frac{26 + 13}{12}] = \frac{39}{4} \div \frac{39}{12} (Removing square brackets) = \frac{39}{4} \times \frac{12}{39} = 3 (Removing' \div')$

Page No 107:

Answer:

Given expression:
$= 4 \frac{1}{10} - [2 \frac{1}{2} - \{\frac{5}{6} - (\frac{2}{5} + \frac{3}{10} - \frac{4}{15})\}] = \frac{41}{10} - [\frac{5}{2} - \{\frac{5}{6} - (\frac{2}{5} + \frac{3}{10} - \frac{4}{15})\}] = \frac{41}{10} - [\frac{5}{2} - \{\frac{5}{6} - (\frac{12 + 9 - 8}{30})\}] = \frac{41}{10} - [\frac{5}{2} - \{\frac{5}{6} - \frac{13}{30}\}] (Removing parentheses) = \frac{41}{10} - [\frac{5}{2} - \{\frac{25 - 13}{30}\}] = \frac{41}{10} - [\frac{5}{2} - \frac{12}{30}] (Removing braces) = \frac{41}{10} - [\frac{75 - 12}{30}] = \frac{41}{10} - \frac{63}{30} (Removing square brackets) = \frac{123 - 63}{30} = \frac{60}{30} = 2$

Page No 107:

Answer:

Given expression:
$= 1 \frac{5}{6} + [2 \frac{2}{3} - \{3 \frac{3}{4} (3 \frac{4}{5} \div 9 \frac{1}{2})\}] = \frac{11}{6} + [\frac{8}{3} - \{\frac{15}{4} (\frac{19}{5} \div \frac{19}{2})\}] = \frac{11}{6} + [\frac{8}{3} - \{\frac{15}{4} (\frac{19}{5} \times \frac{2}{19})\}] = \frac{11}{6} + [\frac{8}{3} - \{\frac{15}{4} \times \frac{2}{5}\}] (Removing parentheses) = \frac{11}{6} + [\frac{8}{3} - \frac{3}{2}] (Removing braces) = \frac{11}{6} + [\frac{16 - 9}{6}] = \frac{11}{6} + \frac{7}{6} (Removing square brackets) = \frac{18}{6} = 3$

Page No 107:

Answer:

Given expression:
$= 4 \frac{4}{5} \div \{2 \frac{1}{5} - \frac{1}{2} (1 \frac{1}{4} - \frac{1}{4} - \frac{1}{5})\} = \frac{24}{5} \div \{\frac{11}{5} - \frac{1}{2} (\frac{5}{4} - \frac{1}{4} - \frac{1}{5})\} = \frac{24}{5} \div \{\frac{11}{5} - \frac{1}{2} (\frac{5}{4} - \frac{1}{20})\} (Removing bar) = \frac{24}{5} \div \{\frac{11}{5} - \frac{1}{2} (\frac{25 - 1}{20})\} = \frac{24}{5} \div \{\frac{11}{5} - \frac{1}{2} \times \frac{24}{20}\} (Removing parentheses) = \frac{24}{5} \div \{\frac{11}{5} - \frac{12}{20}\} (Removing' \times') = \frac{24}{5} \div \{\frac{44 - 12}{20}\} = \frac{24}{5} \div \frac{32}{20} (Removing braces) = \frac{24}{5} \times \frac{20}{32} (Removing' \div') = \frac{3}{4} \times 4 = 3$

Page No 107:

Answer:

Given expression:
$= 7 \frac{1}{2} - [2 \frac{1}{4} \div \{1 \frac{1}{4} - \frac{1}{2} (\frac{3}{2} - \frac{1}{3} - \frac{1}{6})\}] = \frac{15}{2} - [\frac{9}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{3}{2} - \frac{1}{3} - \frac{1}{6})\}] = \frac{15}{2} - [\frac{9}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{3}{2} - \frac{1}{6})\}] (Removing bar) = \frac{15}{2} - [\frac{9}{4} \div \{\frac{5}{4} - \frac{1}{2} (\frac{9 - 1}{6})\}] = \frac{15}{2} - [\frac{9}{4} \div \{\frac{5}{4} - \frac{1}{2} \times \frac{4}{3}\}] (Removing parentheses) = \frac{15}{2} - [\frac{9}{4} \div \{\frac{5}{4} - \frac{2}{3}\}] (Removing' \times') = \frac{15}{2} - [\frac{9}{4} \div \{\frac{15 - 8}{12}\}] (Removing braces) = \frac{15}{2} - [\frac{9}{4} \div \frac{7}{12}] = \frac{15}{2} - [\frac{9}{4} \times \frac{12}{7}] (Removing' \div') = \frac{15}{2} - \frac{27}{7} (Removing square brackets) = \frac{105 - 54}{14} = \frac{51}{14} = 3 \frac{9}{14}$

Page No 108:

Answer:

(c ) 18

Explanation:
= 8 + 4 ÷ 2 × 5
= 8 + 2 × 5
= 8 + 10 = 18

Page No 108:

Answer:

( b ) 12

Explanation:
= 54 ÷ 3 of 6 + 9
= 54 ÷ (3 x 6) + 9
= 54 ÷ 18 + 9
= 3 + 9 = 12

Page No 108:

Answer:

(b ) 3

Explanation:
= 13 - (12 - 6 ÷ 3)
= 13 - (12 - 2)
= 13 - 10 = 3

Page No 108:

Answer:

(a ) 7

Explanation:
= 1001 ÷ 11 of 13
= 1001 ÷ ( 11 x 13)
= 1001 ÷ 143 = 7

Page No 108:

Answer:

(b) 121

Explanation:
Given expression:
= 133 + 28 $\div$ 7 - 8 ⨯ 2
= 133 + 4 - 8 ⨯2 [Performing division]
= 133 + 4 - 16     [Performing multiplication]
= 137 - 16     [Performing addition]
= 121    [Performing subtraction]

Page No 108:

Answer:

(a) 3636

Explanation:
Given expression:
= 3640 - 14 $\div$ 7 ⨯ 2
= 3640 - 2 ⨯2 [Performing division]
= 3640 - 4 [Performing multiplication]
= 3636 [Performing subtraction]

Page No 108:

Answer:

(b) 920

Explanation:
Given expression:
= 100 ⨯ 10 $-$ 100 + 2000 $\div$ 100
= 100 ⨯ 10 $-$ 100 + 20    [Performing division]
= 1000 $-$ 100 + 20    [Performing multiplication]
= 1020 $-$ 100 [Performing addition]
= 920          [Performing subtraction]

Page No 108:

Answer:

(b) 23
Explanation:

Given expression:
= 27 $-$ [18 $-$ {16 $-$ (5 $-$ $4 - 1$ )}]
=  27 $-$ [18 $-$ {16 $-$ (5 $-$ 3)}] (Removing bar)
= 27 $-$ [18 $-$ {16 $-$ 2}] (Removing parentheses)
= 27 $-$ [18 $-$ 14]    (Removing braces)
= 27 $-$ 4    (Removing square brackets)
= 23

Page No 108:

Answer:

(a) 29
Explanation:
Given expression:
= 32 $-$ [48 $\div$ {36 $-$ ( 27 $-$ $16 - 9$ )}]
= 32 $-$ [48 $\div$ {36 $-$ ( 27 $-$ 7)}]    (Removing bar)
= 32 $-$ [48 $\div$ {36 $-$ 20}]    (Removing parentheses)
= 32 $-$ [48 $\div$ 16]   (Removing braces)
= 32 $-$ 3    (Removing square brackets)
= 29

Page No 108:

Answer:

(a ) 6

Explanation:
Given expression:
= 8 $-$ [28 ÷ {34 $-$ (36 $-$ 18 ÷ 9 × 8)}] [Performing division]
= 8 $-$ [28 ÷ {34 $-$ (36 $-$ 2 × 8)}] [Performing multiplication]
= 8 $-$ [28 ÷ {34 $-$ (36 $-$ 16)}]
= 8 $-$ [28 ÷ {34 $-$ 20}]    [Removing parentheses]
= 8 $-$ [28 ÷ 14]   [Removing braces]
= 8 $-$ 2 = 6       [Removing square brackets]

Page No 109:

Answer:

We have:
16 - [11 + {8 - (6 - $4 - 2$ )}]
= 16 - [11 + {8 - (6 - 2)}] (Removing bar)
= 16 - [11 + {8 - 4}]
= 16 - [11 + 4]     (Removing barces)
= 16 - 15    (Removing square brackets)
= 1

Page No 109:

Answer:

We have:
16 + 8 $\div$ 4 $-$ 2 $\times$ 3
= 16 + 2 $-$ 2 $\times$ 3 (Division)
= 16 + 2 $-$ 6 (Multiplication)
= 18 $-$ 6 (Addition)
= 12

Page No 109:

Answer:

Given expression:
36 - [18 - {14 - (15 - 4 ÷ 2 × 2)}] [Performing division]
= 36 - [18 - {14 - (15 - 2 × 2)}]       [Performing multiplication]
= 36 - [18 - {14 - (15 - 4)}]
= 36 - [18 - {14 - 11}]    [Removing parentheses]
= 36 - [18 - 3]        [Removing braces]
= 36 - 15     [Removing square brackets]
= 21

Page No 109:

Answer:

Page No 109:

Answer:

(c) $27 \frac{5}{7}$
We have:
16 - 2 ÷ 7 + 6 × 2
= 16 - $(\frac{2}{7})$ + 6 × 2 [Performing division]
= 16 - $(\frac{2}{7})$ + 12    [Performing multiplication]
= 28 - $(\frac{2}{7})$     [Performing addition]
= $\frac{28}{1} - \frac{2}{7} = \frac{(196 - 2)}{7} = \frac{194}{7} = 27 \frac{5}{7}$    [Performing subtraction]

Page No 109:

Answer:

(b)12

We have:
54 ÷ 3 of 6 + 9
= 54 ÷ 18 + 9
= 3 + 9
= 12

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