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Page No 29:

Question 1:

All genes located on the same chromosome:

a. Form different groups depending upon their relative distance
b. Form one linkage group
c. Will not from any linkage groups
d. Form interactive groups that affect the phenotype

Answer:

The genus located on the same chromosomes form one linkage group. It is defined as all the genes located on a single chromosome moves as a unit at the time of all division. Genes do not tend to separate until the crossing over occurs and if the distance between the two genus is very less, crossing over does not takes place.

Hence, the correct answer is option c.

Page No 29:

Question 2:

Conditions of a karyotype 2n +1, 2n –1 and 2n + 2, 2n – 2 are called:

a. Aneuploidy
b. Polyploidy
c. Allopolyploidy
d. Monosomy

Answer:

Aneuploidy is caused due to the failure of segregation of chromatids during cell division results in gain or loss of chromosomes.

For example:-
Down's syndrome us caused due to the gain in one extra copy of chromosomes 21.
Turner syndrome is caused due to the loss of an X-chromosome in human females.

Hence, the correct answer is option a.

Page No 29:

Question 3:

Distance between the genes and percentage of recombination shows:

a. a direct relationship
b. an inverse relationship
c. a parallel relationship
d. no relationship

Answer:

Linkage is the a term used to describe physical association of genes on a chromosome. While recombination is a term used to describe the generation of non-parental gene combinations. The distance between the two genes has direct relationship with the recombination percentage as with the increase in distance between the genes, the recombination percentage increases.

Hence, the correct answer is option a.

Page No 29:

Question 4:

If a genetic disease is transferred from a phenotypically normal but carrier female to only some of the male progeny, the disease is:

a. Autosomal dominant
b. Autosomal recessive
c. Sex-linked dominant
d. Sex-linked recessive

Answer:

In a sex-linked recessive disease, the genetic disorder is passed on from unaffected carrier female to the male progeny. For example, haemophilia, in this genetic disorder, an heterozygous carrier female for haemophilia can transmit the disease to their sons.

Hence, the correct answer is option d.



Page No 30:

Question 5:

In sickle cell anaemia glutamic acid is replaced by valine. Which one of the following triplets codes for valine?

a. G G G
b. A A G
c. G A A
d. G U G

Answer:

The triples GUG codes for the aminoacid valine. Sickle cell anaemia is a genetic defect caused due to the substitution of glutamic acid (Glu) by Valine (Val) at the sixth position of the beta-globin chain of the haemoglobin molecule. The substitution of amino acid in the globin protein results due to the single base substitution at the sixth codon of the beta globin gene from GAG TO GUG.

Hence, the correct answer is option d.

Page No 30:

Question 6:

Person having genotype IA IB would show the blood group as AB. This is because of:

a. Pleiotropy
b. Co-dominance
c. Segregation
d. Incomplete dominance

Answer:

When the alleles IA and IB are present together, the both express their own types of sugars because of co-dominance. This is expressed as blood group AB.

Hence, the correct answer is option b.

Page No 30:

Question 7:

Z Z / ZW type of sex determination is seen in:

a. Platypus
b. Snails
c. Cockroach
d. Peacock

Answer:

In birds, two different types of gametes in terms of sex chromosomes are produced by females and is called female heterogamety. The two different sex chromosomes of a female bird is designated as ZW. While the male birds have a pair of ZZ chromosomes.

Hence, the correct answer is option d.

Page No 30:

Question 8:

A cross between two tall plants resulted in offspring having few dwarf plants. What would be the genotypes of both the parents?

a. TT and Tt
b. Tt and Tt
c. TT and TT
d. Tt and tt

Answer:

When a cross is made between two heterozygous tall plants(Tt), the offsprings produced are tall and dwarf. This can be best explained by a genetic cross:-

Figure

Tall: Dwarf

Hence, the correct answer is option b.

Page No 30:

Question 9:

In a dihybrid cross, if you get 9:3:3:1 ratio it denotes that:

a. The alleles of two genes are interacting with each other
b. It is a multigenic inheritance
c. It is a case of multiple allelism
d. The alleles of two genes are segregating independently.

Answer:

Mendel Law of Independent Assortment states that "when two pairs of traits are combined in a hybrid, the segregation of one pair of characters is independent of the other pair of characters". The ratio of 9 : 3 : 3 : 1 in a dihybrid cross denotes that the alleles of two genes are segregating independently.

Hence, the correct answer is option d.

Page No 30:

Question 10:

Which of the following will not result in variations among siblings?

a. Independent assortment of genes
b. Crossing over
c. Linkage
d. Mutation

Answer:

Linkage is a term used to describe the physical association of genes on a chromosome. The linked genes occurs on the same chromosome and they are transmitted together. In this process, there will be a tendency to maintain the parental gene combinations except in the case of occasional crossovers. So, Linkage is a phenomenon that will not result in variations among siblings.

Hence, the correct answer is option c.



Page No 31:

Question 11:

Mendel’s Law of independent assortment holds good for genes situated on the:

a. non-homologous chromosomes
b. homologous chromosomes
c. extra nuclear genetic element
d. same chromosome

Answer:

Mendel’s Law of Independent Assortment states that 'when two pairs of traits are combined in a hybrid, the segregation of one pair of characters us independent of the other pair of characters'.

Hence, the correct answer is option .

Page No 31:

Question 12:

Occasionally, a single gene may express more than one effect. The phenomenon is called:

a. multiple allelism
b. mosaicism
c. pleiotropy
d. polygeny

Answer:

Pleiotropic gene are single gene that can exhibit multiple phenotyphic expression and this phenomenon is called pleiotropy. For example : phenylketonuria in humans. This disease is caused due to mutation in a gene that codes for phenylalanine hydroxylase enzyme (single gene mutation). The effect represents itself through phenotypic expressions which is characterised by mental retardation and reduction in hair and skin pigmentation.

Hence, the correct answer is option c.

Page No 31:

Question 13:

In a certain taxon of insects some have 17 chromosomes and the others have 18 chromosomes. The 17 and 18 chromosome-bearing organisms are:

a. males and females, respectively
b. females and males, respectively
c. all males
d. all females

Answer:

XQ- XX type of sex determination mechanism is seen in insects. Males produce two different types of gametes, (a) either with or without chromosomes or (b) some gametes with X-chromosomes and some with Y-chromosomes. In this type of sex determination, mechanism, males have only 18 chromosomes with autosomes while females have a pair of X-chromosomes with autosomes.
Males have 17 chromosomes while females have 18 chromosomes.

Hence, the correct answer is option a.

Page No 31:

Question 14:

The inheritance pattern of a gene over generations among humans is studied by the pedigree analysis. Character studied in the pedigree analysis is equivalent to:

a. quantitative trait
b. Mendelian trait
c. polygenic trait
d. maternal trait

Answer:

Pedigree analysis is the inheritance of a particular trait is represented in a family tree over generations. This acts as a strong tool and is utilised to trace the inheritance of a specific trait, abnormality or diseases. So, this indicates that Mendelian principles are applicable to human genetics and the character studied in the pedigree analysis is equivalent to mendelian traits.

Hence, the correct answer is option b.

Page No 31:

Question 15:

It is said that Mendel proposed that the factor controlling any character is discrete and independent. His proposition was based on the

a. results of F3 generation of a cross.
b. observations that the offspring of a cross made between the plants having two contrasting characters shows only one character without any blending.
c. self pollination of F1 offsprings
d. cross pollination of F1 generation with recessive parent

Answer:

It was observed by the Mendel's law that when two pairs of different characters are analyzed in a dihybrid cross. The behaviour of a specific character is independent of another character.

Hence, the correct answer is option b.



Page No 32:

Question 16:

Two genes ‘A’ and ‘B’ are linked. In a dihybrid cross involving these two genes, the F1 heterozygote is crossed with homozygous recessive parental type (aa bb). What would be the ratio of offspring in the next generation?

a. 1 : 1 : 1: 1
b. 9 : 3 : 3 : 1
c. 3 : 1
d. 1 : 1

Answer:

Figure
 

 
 
 
 
 
ab
AB
Ab
aB
ab
 
AaBb
Aabb
aaBb
aabb

Ratio:- 1 : 1 : 1 : 1

Hence, the correct answer is option a.

Page No 32:

Question 17:

In the F2 generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are:

a. phenotypes - 4; genotypes - 16
b. phenotypes - 9; genotypes - 4
c. phenotypes - 4; genotypes - 8
d. phenotypes - 4; genotypes - 9

Answer:

In a dihybrid cross, the number of phenotypes are 4 (round yellow, round green, wrinkled yellow, wrinkled green) while the number of genotypes are 9.

Hence, the correct answer is option d.

Page No 32:

Question 18:

Mother and father of a person with ‘O’ blood group have ‘A’ and ‘B’ blood group, respectively. What would be the genotype of both mother and father?

a. Mother is homozygous for ‘A’ blood group and father is heterozygous for ‘B’
b. Mother is heterozygous for ‘A’ blood group and father is homozygous for ‘B’
c. Both mother and father are heterozygous for ‘A’ and ‘B’ blood group, respectively
d. Both mother and father are homozygous for ‘A’ and ‘B’ blood group, respectively

Answer:

Figure

It is evident from the above-mentioned cross that the genotypes of mother and father are IAIO and IBIO.

Hence, the correct answer is option c.

Page No 32:

Question 1:

What is the cross between the progeny of F1 and the homozygous recessive parent called? How is it useful?

Answer:

A cross is made between the F1 progeny and homozygous recessive parent is called test cross. This cross is used you the determination of the genotype of an unknown dominant parents.

Page No 32:

Question 2:

Do you think Mendel’s laws of inheritance would have been different if the characters that he chose were located on the same chromosome.

Answer:

Yes, the Mendel's law of inheritance would have been different it the characters were located on the same chromosome because they would not assort independently and linkage percentage depends on the distance between the two genes.

Page No 32:

Question 3:

Enlist the steps of controlled cross pollination. Would emasculation be needed in a cucurbit plant? Give reasons for your answer.

Answer:

Steps involved in cross-pollination are:-
(i) Selection of parents with desired characters.
(ii) Emasculation and bagging techniques are done to protect the stigma from contamination.
Cucurbits are bisexuals plants that have both male and female flowers on the same plant. Self-pollination occurs in such plants and emasculation is required to prevent contamination.

Page No 32:

Question 4:

A person has to perform crosses for the purpose of studying inheritance of a few traits / characters. What should be the criteria for selecting the organisms?

Answer:

(i) The organisms must have easily identifiable sets of contrasting characters.
(ii) They have short life cycle so that their study can be completed within a couple of years.
(iii) Hybridization is easily induced in that organism.



Page No 33:

Question 5:

The pedigree chart given below shows a particular trait which is absent in parents but present in the next generatoin irrespective of sexes. Draw your conclusion on the basis of the pedigree.

Answer:

The given Pedigree chart represents autosomal recessive trait. Both the parents are carriers (heterozygous condition), so one male and female offspring are suffering from genetic disorder while the other two are either carrier or normal.

Page No 33:

Question 6:

In order to obtain the F1 generation Mendel pollinated a pure-breeding tall plant with a pure breeding dwarf plant. But for getting the F2 generation, he simply self-pollinated the tall F1 plants. Why?

Answer:

To obtain the F1 generation, Mendel pollinated a pure-breeding tall plant (TT) with a pure-breeding dwarf plant (tt) and the progenies obtained were all tall.
Figure
The progeny obtained in F1 generation are heterozygous and allow self-pollination to raise F2 offspring. 50% genotype of the offspring would resemble one parent and the rest to the other parent. He also wants to understand the inheritance of the selected trait over several generations.

Page No 33:

Question 7:

“Genes contain the information that is required to express a particular trait.” Explain.

Answer:

Figure
The genes found in an organism express a specific trait by forming a certain products and this can be achieved by the process of transcription and translation (Central dogma).

Page No 33:

Question 8:

How are alleles of particular gene differ from each other? Explain its significance.

Answer:

Alleles are the polymorphs and have different nucleotide sequences results in different phenotypic expression. They are the alternative forms of a same gene.
For example: Genes that codes for height have  2 allele:- one for dwarfness (tt) and one for tallness(TT)
Significance:
They are responsible for variation in the population, as a character.

Page No 33:

Question 9:

In a monohybrid cross of plants with red and white flowered plants, Mendel got only red flowered plants. On self-pollinating these F1 plants got both red and white flowered plants in 3:1 ratio. Explain the basis of using RR and rr symbols to represent the genotype of plants of parental generation.

Answer:

Genetic cross:-
Figure

Selfing:-
Figure

3 : 1
In this cross the upper case letters are used to denote dominant characteristics while the lower case letters are used to denote the recessive characteristics of the same alleles. It shows a monohybrid cross with 3 : 1 in the F2 generation.
It indicates that the parents must be true-breed and parents are diploid as well as homologous chromosomes carry alliles with same type. They are represented by RR and rr.

Page No 33:

Question 10:

For the expression of traits genes provide only the potentiality and the environment provides the opportunity. Comment on the veracity of the statement.

Answer:

Yes, genes are not only responsible for the determination of phenotype. As, environment is also responsible for the expression of traits. They are active throughout the lives, switching their expressions on and off according to the change in environmental condition. Apart from internal factors such as hormones and metabolism affects the gene expression, external factors such as temperature, light, nutrition and so on also affects the gene expression and exhibit phenotypic changes.

Page No 33:

Question 11:

A, B, D are three independently assorting genes with their recessive alleles a, b, d, respectively. A cross was made between individuals of Aa bb DD genotype with aa bb dd. Find out the type of genotypes of the offspring produced.

Answer:

The genotypes of offspring produced are:-
 

  abd
AbD AabbDd
abD aabbDd

Hence, the genotypes of offsprings are:-
AabbDd and aabbDd

Page No 33:

Question 12:

In our society a woman is often blamed for not bearing male child. Do you think it is right? Justify.

Answer:

Human have 23 pairs of chromosomes and out of them, 22 pairs are autosomes. They are same in both male and female. Males have one X and Y chromosomes (sex chromosome) while females have two X chromosomes. When the ovum fertilises with the sperm carrying X-chromosome, the zygote develops into a female (XX). When the ovum fertises with the sperm carrying Y-chromosome, the zygote develops into a male (XY). It is evident that father is responsible for the sex of child and there is always 50 percent probability of either a male or female child.

Page No 33:

Question 13:

Discuss the genetic basis of wrinkled phenotype of pea seed.

Answer:

The shape of pea seeds (round and wrinkled) are controlled by two alleles (Rr). R is dominant allele for round seed shape while r is recessive allele for wrinkled seed shape. The phenotype for wrinkled seed shape is shown when genotype contains both the recessive alleles and is represented by rr.

Page No 33:

Question 14:

Even if a character shows multiple allelism, an individual will only have two alleles for that character. Why?

Answer:

Most of the organisms are diploid in nature and the alleles are present only in pairs. So, apart from multiple allelism, an individual will have only two alleles because individual develops from a zygote. It is formed by the fusion of male and female gametes. So, the egg and sperm contain one gene for each trait and the zygote formed is diploid as they have two alleles for each trait.
For example:- ABO blood grouping in humans as they have IA, and IB i alleles but any given blood group has only two alleles, like AB blood group (IAIB) or O blood group (ii).

Page No 33:

Question 15:

How does a mutagen induce mutation? Explain with example.

Answer:

There are several chemical and physical factors that can induce mutations and they are called mutagens. Mutagens induce mutation by altering the sequence of nitrogenous base pair of DNA during the process of DNA replication. Ethylmethanesulfonate (EMS) is a chemical mutagen that can induce mutation in the genome of fly.

Page No 33:

Question 1:

In a Mendelian monohybrid cross, the F2 generation shows identical genotypic and phenotypic ratios. What does it tell us about the nature of alleles involved? Justify your answer.

Answer:

The plants produced in a F1 generation, are when allowed to reproduce without a genetic cross, the alleles segregate. In this, one alleles goes to one parent while the another allele goes to one another parent and this process is similar to the transfer of halved the number of chromosome during meiosis. The process of segregation is a random process and there will be 50%, chance of a specific allele to become either male gamete our female gamete and because of this, the genotypes produced by F2 generation is same as that with the phenotype produced in the same generation. Hence, the plants produced with pure genotypes and those produced with mixed genotypes will be the
same (50%).



Page No 34:

Question 2:

Can a child have blood group O if his parents have blood group ‘A’ and ‘B’. Explain.

Answer:

If the parents have blood group IA IO and IB IO (heterozygous condition) then their will be a possibility for a child born having O blood group. It can be best explained with the help of a given genetic cross.

Figure

It is evident from the above-mentioned cross that if the genotypes of the parents is IA IO and IB IO, the child born have O blood group.

Page No 34:

Question 3:

What is Down’s syndrome? Give its symptoms and cause. Why is it that the chances of having a child with Down’s syndrome increases if the age of the mother exceeds forty years?

Answer:

Down syndrome is a genetic disorder caused due to the presence of an additional copy of chromosome number 21 (trisomy of 21 chromosome) This is first described by Langdon Down in 1866.
Symptoms:
The affected individuals are short statured with small round head, furrowed tongue and partially open mouth. Their palm is broad with characteristics palm crease, physical, psychomotor and mental development is retarded.
With the increase in age of females above 40, the chances of having a child with Down's syndrome increases because ova or egg cells are present in females since birth and older eggs cells are more prone to chromosomal non-disjunction due to several physical and chemical factors.

Page No 34:

Question 4:

How was it concluded that genes are located on chromosomes?

Answer:

Walter Sutton and Theodore Boveri observed that the behaviour of chromosomes was parallel to the behaviour of genes. They have studied the behaviour of chromosomes during mitosis and meiosis. The chromosomes and genes occurs in pairs from this study they have concluded that the genes are located on chromosome.

Page No 34:

Question 5:

A plant with red flowers was crossed with another plant with yellow flowers. If F1 showed all flowers orange in colour, explain the inheritance.

Answer:

When a plant with red flowers and crossed with plant having yellow flowers, orange flowers are produced in the F1 generation. This type of inheritance is called incomplete dominance.
In this type of inheritance, the phenotype produced during F1 generation did not resemble either of the two parents and was in between the two.
This can be explained with the help of a genetic cross:-
Figure

Page No 34:

Question 6:

What are the characteristic features of a true-breeding line?

Answer:

The characteristics of true-breeding lines are:-
(i) They must be self-pollinating for several generations.
(ii) They must be able to stable trait inheritance for several generations.
(iii) They must show stable expression of characters for several generations.

Page No 34:

Question 7:

In peas, tallness is dominant over dwarfness, and red colour of flowers is dominant over the white colour. When a tall plant bearing red flowers was pollinated with a dwarf plant bearing white flowers, the different phenotypic groups were obtained in the progeny in numbers mentioned against them:

Tall, Red = 138
Tall, White = 132
Dwarf, Red = 136
Dwarf, White = 128

Mention the genotypes of the two parents and of the four offspring types.

Answer:

Figure

Generation:-

 
TR
tr
Tr
tR
TR
TTRR
TtRr
TTRr
TtRR
tr
TtRr
ttrr
Ttrr
ttRr
Tr
TTRr
Ttrr
TTrr
Ttrr
tR
TtRR
ttRR
TtRr
ttRR

The genotypes for Tall, Red plant = TTRR and TtRr
Dwarf, red = ttRr and ttRR
Tall, White = Ttrr and TTrr
Dwarf, white = ttrr

Page No 34:

Question 8:

Why is the frequency of red-green colour blindness is many times higher in males than that in the females?

Answer:

Colour blindness is a sex-linked inheritance. This disorder is caused due to the defect in either red or green cones of the eye results in failure to discriminate between red and green colour. It occurs commonly in males because the genes responsible for red-green colour blindness are located on X-chromosome and males only have one X-chromosome while female have two X-chromosome. A female will be colourblind only when her mother is carrier or colourblind and father is colourblind.

Page No 34:

Question 9:

If a father and son are both defective in red-green colour vision, is it likely that the son inherited the trait from his father? Comment.

Answer:

Colour blindness is a sex-linked inheritance and genes responsible for the red-green colour blindness are located on X-chromosomes.
The mother is carrier for colour blindness and may passed the genes to her son. As sex-linked inheritance is not transferred from father to son. In this inheritance, the transmission of disease occurs from unaffected carrier female to male progeny.
This can be explained with the help of a given cross:-

Figure

Figeneration

 
XC
X
XC
XCXC
XCX
Y
XCY
XY

Page No 34:

Question 10:

Discuss why Drosophila has been used extensively for genetical studies.

Answer:

Drosophila has been used for genetic studies because
(i) They can be grown on simple synthetic medium in the laboratory.
(ii) They complete their life cycle into two weeks.
(iii) A single mating could produce a large number of progeny flies.
(iv) Male and female flies are easily distinguishable.

Page No 34:

Question 11:

How do genes and chromosomes share similarity from the point of view of genetical studies?

Answer:

The similarities between genes and chromosomes are as follows:-
(i) Both genes and chromosomes occurs in pair.
(ii) They Segregate during gamete formation as only one, of each pair is transmitted into the gametes.
(iii) The independent pairs segregate independently of each other in them.

Page No 34:

Question 12:

What is recombination? Discuss the applications of recombination from the point of view of genetic engineering.

Answer:

Recombination is a process that involves the generation of new combination of genes. It is different from the parental types.
Recombination occurs due to crossing over that takes place at the time of meiosis prior to gamete formation.

Applications of recombinations:-
(i) This process helps in the formation of new combinations of genes and traits.
(ii) It also increases the variability among population that is useful for the process of natural selection under changed environmental condition.
(iii) The frequency of crossing over depends upon the distance between the two genes and this phenomenon is used for the preparation of linkage chromosome maps.

Page No 34:

Question 13:

What is artificial selection? Do you think it affects the process of natural selection? How?

Answer:

Artificial selection is the identification and selection of desirable traits in plants and animals by humans to produce desirable traits.
Yes, the process of artificial selection, affects the process of national selection.
The process of natural selection involves the selection for or against the trait on the basis of their effect on the fitness of the organism.
Natural selection results in the evolution any change in the expression of the trait in the population.
Artificial selection is a faster process but cause threat on the diversity.

Page No 34:

Question 14:

With the help of an example differentiate between incomplete dominance and co-dominance.

Answer:

Codominance
Incomplete dominance
(i) In this type, the phenotypes of two parents are expressed in a hybrid.
(i) In this type, parents are blend together to produce a new phenotype.
(ii) Both the alleles are expressed together and does not mask the effect of each other.
(ii) m this condition, a dominant allele does not completely mask the expressions of a recessive allele.
(iii) For example:- ABO blood grouping in humans. A and B are dominant over O.
(iii) For example:- Antirrhinum majus Ital (Snapdragon)

Page No 34:

Question 15:

It is said, that the harmful alleles get eliminated from population over a period of time, yet sickle cell anaemia is persisting in human population. Why?

Answer:

Sickle cell anaemia is an autosome linked recessive trait. This can be transmitted from parents to the offspring when both the parents are carriers for the gene (heterozygous condition). The disease is controlled by a single pair of a allele HbA and Hb5. Homozygous individuals such as Hb5 Hb5 show the diseased phenotype. While heterozygous individuals are unaffected but they are carrier of the disease. People having sickle cell anemia mutation is protected against malaria which may be the reason of persistance of sickle cell anemia gene in the population.



Page No 35:

Question 1:

In a plant tallness is dominant over dwarfness and red flower is dominant over white. Starting with the parents work out a dihybrid cross. What is standard dihybrid ratio? Do you think the values would deviate if the two genes in question are interacting with each other?

Answer:

A cross between a tall plant with red flowers (TTRR)  and a dwarf plant with white flowers (ttrr). All the plants produce in F1 generation will be tall and produce red flowers (TtRr)
But when the F1 plants are self-pollinated, the phenotype of F2 plants can be represented by punnett square.

Parents Male TTRR X Female ttrr 
Gametes T R   t r
F1 generation  Tt Rr Tall, red plants    
Selfing:
Parents Male TtRr X Female TtRr
Gametes TR Tr tR tr   TR Tr tR tr
​F2 generation***
 
TR
Tr
tR
Tr
TR
TTRR
TTRr
TtRR
TtRr
Tr
TTRr
TTrr
TtRr
TTrr
tR
TtRR
TtRr
ttRR
TtRr
tr
TtRr
TTrr
ttRr
ttrr
Tall plant with red flower = 9
Tall plant with white flower = 3
Dwarf plant with red flower = 3
Dwarf plant with white flower = 1
The ratio of dihybrid cross is 9 : 3 : 3 : 1.
The standard ratio of dihybrid cross work only when the genes responsible for contrasting characters are present on different chromosome. If those genes are present on the same chromosome, they interact with each other and in this case, the ratio of dihybrid cross show variation from the standard hybrid ratio.
 

Page No 35:

Question 2:

a. In humans, males are heterogametic and females are homogametic. Explain. Are there any examples where males are homogametic and females heterogametic?

b. Also describe as to, who determines the sex of an unborn child? Mention whether temperature has a role in sex determination.

Answer:

a. Humans have 23 pairs of chromosomes. Out of them, 22 pairs are autosomes while 23rd chromosome is sex chromosome. Females have two X chromosome and they are homogametic while males have X and Y chromosome and they are heterogametic.
In case of birds, Males have a pair of Z-chromosomes while females have one Z and W chromosome. Female birds produce two different types of gametes i.e., female heterogamety.
b. In humans, the sex of the child is determined by what they inherit from their father. As males have X and Y sex chromosomes while females have two pair of X chromosomes. All children will inherit an X-chromosome from their mother. A child who inherits an X-chromosome from their father will be a girl and one who inherits an Y-chromosome from their father will be a boy.
In some reptiles, for example: Crocodile, temperature is required for the incubation of fertilized eggs helps in the determination of sex of the animals whether it will be male or female. When the crocodile eggs are incubated at higher temperature, led to the birth of male crocodiles.

Page No 35:

Question 3:

A normal visioned woman, whose father is colour blind, marries a normal visioned man. What would be probability of her sons and daughters to be colour blind? Explain with the help of a pedigree chart.

Answer:

Fig.
Colourblindness is a sex-linked recessive disorder caused due to defect in either red or green cone of the eye. This results in the failure to discriminate between red and green colour. The genes responsible for this defect are located on the X-chromosome. So males have one one chromosome while females have two X chromosome.
In this case, female is carrier as her father is colourblind marries a normal man. So, there will be a probability of having one colourblind son, one carrier daughter, 2 normal offsprings (one son and one daughter.)

Page No 35:

Question 4:

Discuss in detail the contributions of Morgan and Sturvant in the area of genetics.

Answer:

Morgan carried out dihybrid cross in Drosophilla to study that genes were sex-linked. For this, he hybridised yellow-bodied, white-eyed female to brown-bodied, red-eyed males. He intercrossed their F1 progeny. He observed that the two genes did not segregate independently to each other and the F2 ratio deviated from the 9 : 3 : 3 : 1 ratio.
He knew that the genes were located on X-chromosome and noticed that when two genes in a dihybrid cross were situated on the same chromosome, the proportion of parental gene combinations were higher than the non-parental type. He attributed this because of the physical association or linkage of the two genes. He coined a term linkage in order to describe the physical associations of genes on a chromosome. While the term recombination is used to describe the formation of non-parental gene combinations.
Morgan and his colleagues also observed that even when the genes were grouped on the same chromosome, some were very tightly linked and show low recombination. Whereas other genes were loosely linked and show higher recombination.
Alfred Sturtevant was the student of Morgan used the frequency of recombination between gene pairs located on the same chromosome as a measure of the distance between genes and 'mapped' their position on the chromosome.

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Question 5:

Define aneuploidy. How is it different from polyploidy? Describe the individuals having following chromosomal abnormalities.

a. Trisomy of 21st Chromosome
b. XXY
c. XO

Answer:

Aneuoploidy: It is an chromosomal abnormality caused due to the failure of segregation of chromatids during cell division that results in gain or loss of a chromosomes.
Polyploidy: It is an chromosomal abnormality that occurs due to failure of cytokinesis after the telophase stage of cell division. It results in an increase in an increase in a whole set of chromosomes in an organism. This condition only occurs in plants.
a. Trisomy of 21st chromosome:
Down syndrome is an genetic disorder caused due to the presence of an additional copy of chromosome number 21 or trisomy of 21 chromosome.
b. XXY: Klinefelter's syndrome is a genetic disorder caused due to the presence of an additional copy of X-chromosome results into a karyotype of 47 + XXY. This occurs in males.
c. XO: Turner's syndrome is a genetic disorder caused due to the absence of one x chromosomes (45 + XO). This occurs in females.



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