Page No 16.10:
Question 1:
Find the slopes of the tangent and the normal to the following curves at the indicted points:
(i)
(ii)
(iii) y = x3 − x at x = 2
(iv) y = 2x2 + 3 sin x at x = 0
(v) x = a (θ − sin θ), y = a(1 − cos θ) at θ = −π/2
(vi) x = a cos3 θ, y = a sin3 θ at θ = π/4
(vii) x = a (θ − sin θ), y = a(1 − cos θ) at θ = π/2
(viii) y = (sin 2x + cot x + 2)2 at x = π/2
(ix) x2 + 3y + y2 = 5 at (1, 1)
(x) xy = 6 at (1, 6)
Answer:
Page No 16.10:
Question 2:
Find the values of a and b if the slope of the tangent to the curve xy + ax + by = 2 at (1, 1) is 2.
Answer:
Page No 16.10:
Question 3:
If the tangent to the curve y = x3 + ax + b at (1, − 6) is parallel to the line x − y + 5 = 0, find a and b.
Answer:
Page No 16.10:
Question 4:
Find a point on the curve y = x3 − 3x where the tangent is parallel to the chord joining (1, −2) and (2, 2).
Answer:
Let (x1, y1) be the required point.
Page No 16.10:
Question 5:
Find the points on the curve y = x3 − 2x2 − 2x at which the tangent lines are parallel to the line y = 2x − 3.
Answer:
Let (x1, y1) be the required point.
Given:
Page No 16.10:
Question 6:
Find the points on the curve y2 = 2x3 at which the slope of the tangent is 3.
Answer:
Let (x1, y1) be the required point.
Given:
Page No 16.10:
Question 7:
Find the points on the curve xy + 4 = 0 at which the tangents are inclined at an angle of 45° with the x-axis.
Answer:
Let the required point be (x1, y1).
Slope of the tangent at this point = tan 45 = 1
Given:
Page No 16.10:
Question 8:
Find the point on the curve y = x2 where the slope of the tangent is equal to the x-coordinate of the point.
Answer:
Let the required point be (x1, y1).
Given:
Page No 16.10:
Question 9:
At what points on the circle x2 + y2 − 2x − 4y + 1 = 0, the tangent is parallel to x-axis?
Answer:
Let the required point be (x1, y1).
We know that the slope of the x-axis is 0.
Given:
Page No 16.10:
Question 10:
At what point of the curve y = x2 does the tangent make an angle of 45° with the x-axis?
Answer:
Let the required point be (x1, y1).
The tangent makes an angle of 45o with the x-axis.
∴ Slope of the tangent = tan 45o = 1
Page No 16.10:
Question 11:
Find the points on the curve y = 3x2 − 9x + 8 at which the tangents are equally inclined with the axes.
Answer:
Let (x1, y1) be the required point.
It is given that the tangent at this point is equally inclined to the axes. It means that the angle made by the tangent with the x-axis is 45.
∴ Slope of the tangent = tan (45) = 1 ...(1)
Page No 16.10:
Question 12:
At what points on the curve y = 2x2 − x + 1 is the tangent parallel to the line y = 3x + 4?
Answer:
Let (x1, y1) be the required point.
The slope of line y = 3x + 4 is 3.
Page No 16.10:
Question 13:
Find the point on the curve y = 3x2 + 4 at which the tangent is perpendicular to the line whose slop is .
Answer:
Let (x1, y1) be the required point.
Slope of the given line =
∴ Slope of the line perpendicular to it = 6
Page No 16.11:
Question 14:
Find the points on the curve x2 + y2 = 13, the tangent at each one of which is parallel to the line 2x + 3y = 7.
Answer:
Let (x1, y1) represent the required point.
The slope of line 2x + 3y = 7 is .
Page No 16.11:
Question 15:
Find the points on the curve 2a2y = x3 − 3ax2 where the tangent is parallel to x-axis.
Answer:
Let (x1, y1) represent the required points.
The slope of the x-axis is 0.
Here,
Page No 16.11:
Question 16:
At what points on the curve y = x2 − 4x + 5 is the tangent perpendicular to the line 2y + x = 7?
Answer:
Let (x1, y1) be the required point.
Slope of the given line =
Slope of the line perpendicular to this line = 2
Page No 16.11:
Question 17:
Find the points on the curve at which the tangents are parallel to the (i) x-axis (ii) y-axis.
Answer:
(i) The slope of the x-axis is 0.
Now, let (x1, y1) be the required point.
(ii) The slope of the y-axis is .
Now, let (x1, y1) be the required point.
Page No 16.11:
Question 18:
Find the points on the curve x2 + y2 − 2x − 3 = 0 at which the tangents are parallel to the x-axis.
Answer:
Let (x1, y1) be the required point.
Page No 16.11:
Question 19:
Find the points on the curve at which the tangents are (i) parallel to x-axis (ii) parallel to y-axis.
Answer:
(i) The slope of the x-axis is 0.
Now, let (x1, y1) be the required point.
(ii) The slope of the y-axis is .
Let (x1, y1) be the required point.
Given:
Page No 16.11:
Question 20:
Who that the tangents to the curve y = 7x3 + 11 at the points x = 2 and x = −2 are parallel.
Answer:
Both slopes are the same. Hence, the tangents at points x = 2 and x = −2 are parallel.
Page No 16.11:
Question 21:
Find the points on the curve y = x3 where the slope of the tangent is equal to the x-coordinate of the point.
Answer:
Let (x1, y1) be the required point.
x coordinate of the point is x1.
Page No 16.27:
Question 1:
Find the equation of the tangent to the curve , at the point .
Answer:
Page No 16.27:
Question 2:
Find the equation of the normal to y = 2x3 − x2 + 3 at (1, 4).
Answer:
Page No 16.27:
Question 3:
Find the equations of the tangent and the normal to the following curves at the indicated points.
(i) y = x4 − bx3 + 13x2 − 10x + 5 at (0, 5) [NCERT]
(ii) y = x4 − 6x3 + 13x2 − 10x + 5 at x = 1 [NCERT, CBSE 2011]
(iii) y = x2 at (0, 0) [NCERT]
(iv) y = 2x2 − 3x − 1 at (1, −2)
(v)
(vi) y = x2 + 4x + 1 at x = 3 [CBSE 2004]
(vii)
(viii)
(ix) y2 = 4ax at
(x)
(ix) xy = c2 at
(xii)
(xiii) [NCERT]
(xiv) = 2 at (1, 1) [NCERT]
(xv) x2 = 4y at (2, 1)
(xvi) y2 = 4x at (1, 2) [NCERT]
(xvii) 4x2 + 9y2 = 36 at (3cosθ, 2sinθ) [CBSE 2011]
(xviii) y2 = 4ax at (x1, y1) [CBSE 2012]
(xix) [CBSE 2014]
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)
(xi)
(xii)
(xiii)
(xiv)
(xv)
(xvi)
(xvii) Equation of tangent:
(xviii)
(xix)
Page No 16.28:
Question 4:
Find the equation of the tangent to the curve x = θ + sin θ, y = 1 + cos θ at θ = π/4.
Answer:
Page No 16.28:
Question 5:
Find the equations of the tangent and the normal to the following curves at the indicated points.
(i) x = θ + sinθ, y = 1 + cosθ at θ =
(ii)
(iii) x = at2, y = 2at at t = 1
(iv) x = asect, y = btant at t
(v) x = a(θ + sinθ), y = a(1 − cosθ) at θ
(vi) x = 3cosθ − cos3θ, y = 3sinθ − sin3θ [NCERT EXEMPLAR]
Answer:
(i)
(ii) Equation of tangent:
(iii)
Equation of normal:
(iv)
(v)
(vi)
Page No 16.28:
Question 6:
Find the equation of the normal to the curve x2 + 2y2 − 4x − 6y + 8 = 0 at the point whose abscissa is 2.
Answer:
Abscissa means the horizontal co-ordiante of a point.
Given that abscissa = 2.
i.e., x = 2
In both cases, the equation of normal is x = 2
Page No 16.28:
Question 7:
Find the equation of the normal to the curve ay2 = x3 at the point (am2, am3).
Answer:
Page No 16.28:
Question 8:
The equation of the tangent at (2, 3) on the curve y2 = ax3 + b is y = 4x − 5. Find the values of a and b.
Answer:
The slope of the given line y = 4x − 5 is 4
Page No 16.28:
Question 9:
Find the equation of the tangent line to the curve y = x2 + 4x − 16 which is parallel to the line 3x − y + 1 = 0.
Answer:
Let (x0, y0) be the point of intersection of both the curve and the tangent.
Page No 16.28:
Question 10:
Find an equation of normal line to the curve y = x3 + 2x + 6 which is parallel to the line x + 14y + 4 = 0.
Answer:
Let (x1, y1) be a point on the curve where we need to find the normal.
Slope of the given line =
Page No 16.28:
Question 11:
Determine the equation(s) of tangent (s) line to the curve y = 4x3 − 3x + 5 which are perpendicular to the line 9y + x + 3 = 0.
Answer:
Let (x1, y1) be a point on the curve where we need to find the tangent(s).
Slope of the given line =
Since, tangent is perpendicular to the given line,
Slope of the tangent =
Page No 16.28:
Question 12:
Find the equation of a normal to the curve y = x loge x which is parallel to the line 2x − 2y + 3 = 0.
Answer:
Slope of the given line is 1
Page No 16.28:
Question 13:
Find the equation of the tangent line to the curve y = x2 − 2x + 7 which is (i) parallel to the line 2x − y + 9 = 0 (ii) perpendicular to the line 5y − 15x = 13.
Answer:
(i) Slope of the given line is 2
(ii) Slope of the given line is 3
Slope of the line perpendicular to this line =
Page No 16.28:
Question 14:
Find the equations of all lines having slope 2 and that are tangent to the curve .
Answer:
Slope of given tangent = 2
So, there does not exist any such tangent.
Page No 16.28:
Question 15:
Find the equations of all lines of slope zero and that are tangent to the curve .
Answer:
Slope of the given tangent is 0.
Page No 16.28:
Question 16:
Find the equation of the tangent to the curve which is parallel to the 4x − 2y + 5 = 0.
Answer:
Slope of the given line is 2
Page No 16.28:
Question 17:
Find the equation of the tangent to the curve x2 + 3y − 3 = 0, which is parallel to the line y = 4x − 5.
Answer:
Suppose (x1, y1) be the point of contact of tangent.
We can find the slope of the given line by differentiating the equation w.r.t x
So, Slope of the line = 4
Page No 16.29:
Question 18:
Prove that touches the straight line for all n ∈ N, at the point (a, b).
Answer:
So, the given line touches the given curve at the given point.
Page No 16.29:
Question 19:
Find the equation of the tangent to the curve x = sin 3t, y = cos 2t at .
Answer:
Page No 16.29:
Question 20:
At what points will be tangents to the curve y = 2x3 − 15x2 + 36x − 21 be parallel to x-axis? Also, find the equations of the tangents to the curve at these points.
Answer:
Slope of x - axis is 0
Let (x1, y1) be the required point.
Page No 16.29:
Question 21:
Find the equation of the tangents to the curve 3x2 – y2 = 8, which passes through the point (4/3, 0).
Answer:
We have,
3x2 – y2 = 8 ...(i)
Differentiating both sides w.r.t x, we get
Let tangent at (h, k) pass through .
Since, (h, k) lies on (i), we get
Slope of tangent at (h, k) =
The equation of tangent at (h, k) is given by,
Since, the tangent passess through .
Using (ii), we get
So, the points on curve (i) at which tangents pass through are .
Now, from (iii), the equation of tangents are
Page No 16.40:
Question 1:
Find the angle of intersection of the following curves:
(i) y2 = x and x2 = y [NCERT EXEMPLAR]
(ii) y = x2 and x2 + y2 = 20
(iii) 2y2 = x3 and y2 = 32x
(iv) x2 + y2 − 4x − 1 = 0 and x2 + y2 − 2y − 9 = 0
(v) and x2 + y2 = ab
(vi) x2 + 4y2 = 8 and x2 − 2y2 = 2
(vii) x2 = 27y and y2 = 8x
(viii) x2 + y2 = 2x and y2 = x
(ix) y = 4 − x2 and y = x2 [NCERT EXEMPLAR]
Answer:
​
Page No 16.40:
Question 2:
Show that the following set of curves intersect orthogonally.
(i) y = x3 and 6y = 7 − x2
(ii) x3 − 3xy2 = −2 and 3x2y − y3 = 2
(iii) x2 + 4y2 = 8 and x2 − 2y2 = 4
Answer:
So, the given curves intersect orthogonally.
So, the given curves intersect orthogonally.
Page No 16.40:
Question 3:
Show that the following curves intersect orthogonally at the indicated points:
(i) x2 = 4y and 4y + x2 = 8 at (2, 1)
(ii) x2 = y and x3 + 6y = 7 at (1, 1)
(iii) y2 = 8x and 2x2 + y2 = 10 at
Answer:
Hence, the given curves intersect orthogonally at the given point.
Hence, the given curves intersect orthogonally at the given point.
Hence, the given curves intersect orthogonally at the given point.
Page No 16.40:
Question 4:
Show that the curves 4x = y2 and 4xy = k cut at right angles, if k2 = 512.
Answer:
Page No 16.40:
Question 5:
Show that the curves 2x = y2 and 2xy = k cut at right angles, if k2 = 8.
Answer:
Page No 16.40:
Question 6:
Prove that the curves xy = 4 and x2 + y2 = 8 touch each other. [NCERT EXEMPLAR]
Answer:
Page No 16.40:
Question 7:
Prove that the curves y2 = 4x and x2 + y2 6x + 1 = 0 touch each other at the point (1, 2). [NCERT EXEMPLAR]
Answer:
Page No 16.41:
Question 8:
Find the condition for the following set of curves to intersect orthogonally:
(i)
(ii)
Answer:
(ii) The condition for the curves to intersect orthogonally is given below:
Page No 16.41:
Question 9:
Show that the curves intersect at right angles.
Answer:
Page No 16.41:
Question 10:
If the straight line xcos + ysin = p touches the curve , then prove that a2cos2 b2sin2 = p2.
Answer:
Page No 16.41:
Question 1:
Find the point on the curve y = x2 − 2x + 3, where the tangent is parallel to x-axis.
Answer:
The slope of the x-axis is 0.
Now, let (x1, y1) be the required point.
Here,
Page No 16.41:
Question 2:
Find the slope of the tangent to the curve x = t2 + 3t − 8, y = 2t2 − 2t − 5 at t = 2.
Answer:
Page No 16.41:
Question 3:
If the tangent line at a point (x, y) on the curve y = f(x) is parallel to x-axis, then write the value of .
Answer:
The slope of the x-axis is 0.
Also, the tangent at a point (x, y) on the curve y = f(x) is parallel to the x-axis.
∴ Slope of the tangent = Slope of the x-axis = 0
Page No 16.41:
Question 4:
Write the value of , if the normal to the curve y = f(x) at (x, y) is parallel to y-axis.
Answer:
The slope of the y-axis is .
Also, the normal at (x, y) on the curve y = f(x) is parallel to the y-axis.
∴ Slope of the normal = Slope of the y-axis =
Page No 16.41:
Question 5:
If the tangent to a curve at a point (x, y) is equally inclined to the coordinates axes then write the value of .
Answer:
Because the tangent to the curve at (x, y) is equally inclined to the coordinate axes, the angle made by the tangent with the axes can be .
Page No 16.41:
Question 6:
If the tangent line at a point (x, y) on the curve y = f(x) is parallel to y-axis, find the value of .
Answer:
Slope of the y-axis is .
Also, the tangent at (x, y) on the curve y = f(x) is parallel to the y-axis,
∴ Slope of the tangent, = Slope of the y-axis =
Page No 16.41:
Question 7:
Find the slope of the normal at the point 't' on the curve .
Answer:
Page No 16.41:
Question 8:
Write the coordinates of the point on the curve y2 = x where the tangent line makes an angle with x-axis.
Answer:
Let the required point be (x1, y1).
The tangent makes an angle of 45o with the x-axis.
∴ Slope of the tangent = tan 45o = 1
Page No 16.41:
Question 9:
Write the angle made by the tangent to the curve x = et cos t, y = et sin t at with the x-axis.
Answer:
Page No 16.42:
Question 10:
Write the equation of the normal to the curve y = x + sin x cos x at .
Answer:
Page No 16.42:
Question 11:
Find the coordinates of the point on the curve y2 = 3 − 4x where tangent is parallel to the line 2x + y − 2 = 0.
Answer:
Let (x1, y1) be the required point.
Slope of the given line = 2
Page No 16.42:
Question 12:
Write the equation on the tangent to the curve y = x2 − x + 2 at the point where it crosses the y-axis.
Answer:
When the curve crosses the y-axis, the point on the curve is of the form (0, y).
Here,
Page No 16.42:
Question 13:
Write the angle between the curves y2 = 4x and x2 = 2y − 3 at the point (1, 2).
Answer:
Page No 16.42:
Question 14:
Write the angle between the curves y = e−x and y = ex at their point of intersections.
Answer:
Page No 16.42:
Question 15:
Write the slope of the normal to the curve at the point .
Answer:
Page No 16.42:
Question 16:
Write the coordinates of the point at which the tangent to the curve y = 2x2 − x + 1 is parallel to the line y = 3x + 9.
Answer:
Let (x1, y1) be the required point.
Slope of the given line = 3
Page No 16.42:
Question 17:
Write the equation of the normal to the curve y = cos x at (0, 1).
Answer:
Page No 16.42:
Question 18:
Write the equation of the tangent drawn to the curve at the point (0,0).
Answer:
We have,
Slope at (0, 0) = m =
So, the equation of the tangent at (0,0) is given by,
y = mx
Putting m = 1, we get
The equation of the tangent is y = x.
Page No 16.42:
Question 1:
The equation to the normal to the curve y = sin x at (0, 0) is
(a) x = 0
(b) y = 0
(c) x + y = 0
(d) x − y = 0
Answer:
(c) x + y = 0
Page No 16.42:
Question 2:
The equation of the normal to the curve y = x + sin x cos x at x = π/2 is
(a) x = 2
(b) x = π
(c) x + π = 0
(d) 2x = π
Answer:
(d) 2x = π
Page No 16.42:
Question 3:
The equation of the normal to the curve y = x(2 − x) at the point (2, 0) is
(a) x − 2y = 2
(b) x − 2y + 2 = 0
(c) 2x + y = 4
(d) 2x + y − 4 = 0
Answer:
(a) x − 2y = 2
Page No 16.42:
Question 4:
The point on the curve y2 = x where tangent makes 45° angle with x-axis is
(a) (1/2, 1/4)
(b) (1/4, 1/2)
(c) (4, 2)
(d) (1, 1)
Answer:
(b) (1/4, 1/2)
Let the required point be (x1, y1).
The tangent makes an angle of 45o with the x-axis.
∴ Slope of the tangent = tan 45o = 1
Page No 16.42:
Question 5:
If the tangent to the curve x = a t2, y = 2 at is perpendicular to x-axis, then its point of contact is
(a) (a, a)
(b) (0, a)
(c) (0, 0)
(d) (a, 0)
Answer:
(c) (0, 0)
Let the required point be (x1, y1).
Page No 16.42:
Question 6:
The point on the curve y = x2 − 3x + 2 where tangent is perpendicular to y = x is
(a) (0, 2)
(b) (1, 0)
(c) (−1, 6)
(d) (2, −2)
Answer:
(b) (1, 0)
y = x
The tangent is perpendicular to this line.
∴Slope of the tangent =
Now,
Page No 16.42:
Question 7:
The point on the curve y2 = x where tangent makes 45° angle with x-axis is
(a) (1/2, 1/4)
(b) (1/4, 1/2)
(c) (4, 2)
(d) (1, 1)
Answer:
(b) (1/4, 1/2)
Let the required point be (x1, y1).
The tangent makes an angle of 45o with the x-axis.
∴ Slope of the tangent = tan 45o = 1
Page No 16.42:
Question 8:
The point at the curve y = 12x − x2 where the slope of the tangent is zero will be
(a) (0, 0)
(b) (2, 16)
(c) (3, 9)
(d) none of these
Answer:
(d) none of these
Page No 16.42:
Question 9:
The angle between the curves y2 = x and x2 = y at (1, 1) is
(a)
(b)
(c) 90°
(d) 45°
Answer:
(b)
Page No 16.43:
Question 10:
The equation of the normal to the curve 3x2 − y2 = 8 which is parallel to x + 3y = 8 is
(a) x + 3y = 8
(b) x + 3y + 8 = 0
(c) x + 3y ± 8 = 0
(d) x + 3y = 0
Answer:
(c) x + 3y ± 8 = 0
The slope of line x + 3y = 8 is .
Page No 16.43:
Question 11:
The equations of tangent at those points where the curve y = x2 − 3x + 2 meets x-axis are
(a) x − y + 2 = 0 = x − y − 1
(b) x + y − 1 = 0 = x − y − 2
(c) x − y − 1 = 0 = x − y
(d) x − y = 0 = x + y
Answer:
(b) x + y − 1 = 0 = x − y − 2
Let the tangent meet the x-axis at point (x, 0).
Now,
Page No 16.43:
Question 12:
The slope of the tangent to the curve x = t2 + 3 t − 8, y = 2t2 − 2t − 5 at point (2, −1) is
(a) 22/7
(b) 6/7
(c) −6
(d) none of these
Answer:
(b) 6/7
Page No 16.43:
Question 13:
At what point the slope of the tangent to the curve x2 + y2 − 2x − 3 = 0 is zero
(a) (3, 0), (−1, 0)
(b) (3, 0), (1, 2)
(c) (−1, 0), (1, 2)
(d) (1, 2), (1, −2)
Answer:
(d) (1, 2), (1, −2)
Let (x1, y1) be the required point.
Page No 16.43:
Question 14:
The angle of intersection of the curves xy = a2 and x2 − y2 = 2a2 is
(a) 0°
(b) 45°
(c) 90°
(d) none of these
Answer:
(c) 90°
Page No 16.43:
Question 15:
If the curve ay + x2 = 7 and x3 = y cut orthogonally at (1, 1), then a is equal to
(a) 1
(b) −6
(c) 6
(d) 0
Answer:
(c) 6
Page No 16.43:
Question 16:
If the line y = x touches the curve y = x2 + bx + c at a point (1, 1) then
(a) b = 1, c = 2
(b) b = −1, c = 1
(c) b = 2, c = 1
(d) b = −2, c = 1
Answer:
(b) b = −1, c = 1
We can find the slope of the line by differentiating w.r.t. x.
Slope of the given line = 1
Now,
Page No 16.43:
Question 17:
The slope of the tangent to the curve x = 3t2 + 1, y = t3 −1 at x = 1 is
(a) 1/2
(b) 0
(c) −2
(d) ∞
Answer:
(b) 0
Page No 16.43:
Question 18:
The curves y = aex and y = be−x cut orthogonally, if
(a) a = b
(b) a = −b
(c) ab = 1
(d) ab = 2
Answer:
(c) ab = 1
Page No 16.43:
Question 19:
The equation of the normal to the curve x = a cos3 θ, y = a sin3 θ at the point θ = π/4 is
(a) x = 0
(b) y = 0
(c) c = y
(d) x + y = a
Answer:
(c) x = y
Page No 16.43:
Question 20:
If the curves y = 2 ex and y = ae−x intersect orthogonally, then a =
(a) 1/2
(b) −1/2
(c) 2
(d) 2e2
Answer:
(a) 1/2
Page No 16.43:
Question 21:
The point on the curve y = 6x − x2 at which the tangent to the curve is inclined at π/4 to the line x + y = 0 is
(a) (−3, −27)
(b) (3, 9)
(c) (7/2, 35/4)
(d) (0, 0)
Answer:
(b) (3, 9)
Let (x1, y1) be the point where the given curve intersect the given line at the given angle.
Page No 16.43:
Question 22:
The angle of intersection of the parabolas y2 = 4 ax and x2 = 4ay at the origin is
(a) π/6
(b) π/3
(c) π/2
(d) π/4
Answer:
(c) π/2
Page No 16.43:
Question 23:
The angle of intersection of the curves y = 2 sin2 x and y = cos 2 x at is
(a) π/4
(b) π/2
(c) π/3
(d) none of these
Answer:
(c) π/3
Page No 16.43:
Question 24:
Any tangent to the curve y = 2x7 + 3x + 5
(a) is parallel to x-axis
(b) is parallel to y-axis
(c) makes an acute angle with x-axis
(d) makes an obtuse angle with x-axis
Answer:
(c) makes an acute angle with x-axis
We have, y = 2x7 + 3x + 5
Page No 16.43:
Question 25:
The point on the curve 9y2 = x3, where the normal to the curve makes equal intercepts with the axes is
(a)
(b)
(c)
(d) none of these
Answer:
(a) and (c)
Let (x1, y1) be the required point.
Page No 16.43:
Question 26:
The slope of the tangent to the curve x = t2 + 3t − 8, y = 2t2 − 2t − 5 at the point (2, −1) is
(a)
(b)
(c)
(d)
Answer:
(b)
Given:
x = t2 + 3t − 8 and y = 2t2 − 2t − 5
Thus, the correct option is (b).
Page No 16.43:
Question 27:
The line y = mx + 1 is a tangent to the curve y2 = 4x, if the value of m is
(a) 1
(b) 2
(c) 3
(d)
Answer:
(a) 1
Let (x1, y1) be the required point.
The slope of the given line is m.
We have
Because the given line is a tangent to the given curve at point (x1, y1), this point lies on both the line and the curve.
Page No 16.44:
Question 28:
The normal at the point (1, 1) on the curve 2y + x2 = 3 is
(a) x + y = 0
(b) x − y = 0
(c) x + y + 1 = 0
(d) x − y = 1
Answer:
(b) x − y = 0
Page No 16.44:
Question 29:
The normal to the curve x2 = 4y passing through (1, 2) is
(a) x + y = 3
(b) x − y = 3
(c) x + y = 1
(d) x − y = 1
Answer:
Disclaimer: None of the given options is correct.
View NCERT Solutions for all chapters of Class 15