Nm Shah 2018 Solutions for Class 11 Commerce Economics Chapter 1 Organisation Of Data are provided here with simple step-by-step explanations. These solutions for Organisation Of Data are extremely popular among Class 11 Commerce students for Economics Organisation Of Data Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Nm Shah 2018 Book of Class 11 Commerce Economics Chapter 1 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Nm Shah 2018 Solutions. All Nm Shah 2018 Solutions for class Class 11 Commerce Economics are prepared by experts and are 100% accurate.
Page No 72:
Question 1:
Prepare a statistical table from the following data taking the class width as 7 by inclusive method:
28 | 17 | 15 | 22 | 29 | 21 | 23 | 27 | 18 | 12 |
7 | 2 | 9 | 4 | 6 | 1 | 8 | 3 | 10 | 5 |
20 | 16 | 12 | 8 | 4 | 33 | 27 | 21 | 15 | 9 |
3 | 36 | 27 | 18 | 9 | 2 | 4 | 6 | 32 | 31 |
29 | 18 | 14 | 13 | 15 | 11 | 9 | 7 | 1 | 5 |
37 | 32 | 28 | 26 | 24 |
Answer:
Class Interval | Tally Bars | Frequency (f) |
0 − 7 | 15 | |
8 − 15 | 15 | |
16 − 23 | 10 | |
24 − 31 | 10 | |
32 − 39 | 5 | |
Ʃf = 55 |
Page No 72:
Question 2:
Prepare a discrete series from the following data:
62 | 50 | 57 | 58 | 51 | 53 | 62 | 64 | 60 | 61 |
60 | 51 | 64 | 55 | 55 | 52 | 60 | 65 | 58 | 60 |
59 | 52 | 63 | 56 | 56 | 58 | 64 | 63 | 62 | 60 |
Answer:
Value | Tally Bar | Frequency (f) |
50 | 1 | |
51 | 2 | |
52 | 2 | |
53 | 1 | |
55 | 2 | |
56 | 2 | |
57 | 1 | |
58 | 3 | |
59 | 1 | |
60 | 5 | |
61 | 1 | |
62 | 3 | |
63 | 2 | |
64 | 3 | |
65 | 1 | |
Ʃf = 30 |
Page No 72:
Question 3:
Arrange the following marks in frequency table taking the lowest class interval as (10-20).
85 | 70 | 36 | 80 | 78 | 51 | 69 |
96 | 73 | 73 | 92 | 64 | 49 | 78 |
85 | 75 | 80 | 42 | 85 | 29 | 72 |
72 | 77 | 65 | 73 | 95 | 53 | 43 |
91 | 84 | 72 | 75 | 57 | 59 | 61 |
70 | 61 | 75 | 85 | 23 |
Answer:
Marks | Tally Bar | Frequency (f) |
10 − 20 | ||
20 − 30 | 2 | |
30 − 40 | 1 | |
40 − 50 | 3 | |
50 − 60 | 4 | |
60 − 70 | 5 | |
70 − 80 | 14 | |
80 − 90 | 7 | |
90 − 100 | 4 | |
Ʃf = 40 |
Page No 72:
Question 4:
Change the following into continuous series and convert the series into 'less than' and 'more than' cumulative series :
Marks (mid-values) | 5 | 15 | 25 | 35 | 45 | 55 |
No.of students | 8 | 12 | 15 | 9 | 4 | 2 |
Answer:
Mid Value | Class Interval | Number of Students (f) |
5 15 25 35 45 55 |
0 − 10 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60 |
8 12 15 9 4 2 |
Ʃf = 50 |
Cumulative Series
Less Than | More Than | ||
Marks | Number of Students | Marks | Number of Students |
Less than 10 Less than 20 Less than 30 Less than 40 Less than 50 Less than 60 |
8 8 + 12 = 20 20 + 15 = 35 35 + 9 = 44 44 + 4 = 48 48 + 2 = 50 |
More than 0 More than 10 More than 20 More than 30 More than 40 More than 50 |
50 50 − 8 = 42 42 − 12 = 30 30 − 15 = 15 15 − 9 = 6 6 − 4 = 2 |
Page No 72:
Question 5:
Marks obtained by 24 students in English and Statistics in a class are given below . Prepare two-way frequency distribution table.
S.No | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
Marks in English | 22 | 23 | 23 | 23 | 23 | 24 | 23 | 25 | 22 | 23 | 24 | 24 |
Marks in Statistics | 16 | 16 | 18 | 16 | 16 | 17 | 16 | 19 | 16 | 18 | 18 | 17 |
S.No | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 |
Marks in English | 23 | 25 | 23 | 22 | 27 | 27 | 26 | 28 | 25 | 24 | 23 | 25 |
Marks in Statistics | 16 | 17 | 17 | 17 | 15 | 16 | 18 | 19 | 19 | 16 | 17 | 19 |
Answer:
Marks in English | ||||||||
Marks in Statistics | 22 | 23 | 24 | 25 | 26 | 27 | 28 | Total |
15 | − | − | − | − | − | − | 1 | |
16 | − | − | − | 9 | ||||
17 | − | − | − | 6 | ||||
18 | − | − | − | − | 4 | |||
19 | − | − | − | - | − | 4 | ||
Total | 3 | 9 | 4 | 4 | 1 | 2 | 1 | 24 |
Page No 73:
Question 6:
In a survey ,it was found that 64 families bought milk ( in litres) in the following quantities in a particular month.
19 | 16 | 22 | 9 | 22 | 12 | 39 | 19 | 14 | 23 | 6 | 24 | 16 | 18 | 7 |
17 | 20 | 25 | 28 | 18 | 10 | 24 | 20 | 21 | 10 | 7 | 18 | 28 | 24 | 20 |
14 | 23 | 25 | 34 | 22 | 5 | 33 | 23 | 26 | 29 | 13 | 36 | 11 | 26 | 11 |
37 | 30 | 13 | 8 | 15 | 22 | 21 | 32 | 21 | 31 | 17 | 16 | 23 | 12 | 9 |
15 | 27 | 17 | 21 |
Convert the above data in a frequency distribution making classes of 5-9, 10-14 and so on.
Answer:
Quantity of Milk (kg) |
Tally Bar | Frequency (f) |
5 − 9 | 7 | |
10 − 14 | 10 | |
15 − 19 | 13 | |
20 − 24 | 18 | |
25 − 29 | 8 | |
30 − 34 | 5 | |
35 − 39 | 3 | |
Ʃf = 64 |
Page No 73:
Question 7:
The marks obtained by 20 students in Statistics and Economics are given below . Prepare a bivariate frequency distribution.
Marks in Statistics | 10 | 11 | 10 | 11 | 11 | 14 | 12 | 12 | 13 | 10 | 13 | 12 | 11 | 12 | 10 | 14 | 14 | 12 | 13 | 10 |
Marks in Economics | 20 | 21 | 22 | 21 | 23 | 23 | 22 | 21 | 24 | 25 | 24 | 23 | 22 | 23 | 22 | 22 | 24 | 20 | 24 | 23 |
Answer:
Marks in Economics | |||||||
Marks in Statistics | 20 | 21 | 22 | 23 | 24 | 25 | Total |
10 | − | − | 5 | ||||
11 | − | − | − | 4 | |||
12 | − | − | 5 | ||||
13 | − | − | − | − | − | 3 | |
14 | − | − | 3 | ||||
Total | 2 | 3 | 5 | 5 | 4 | 1 | 20 |
Page No 73:
Question 8:
Prepare 'less than' and 'more than' cumulative frequency distributions of the following date:
Wages (₹) | : | 140-150 | 150-160 | 160-170 | 170-180 | 180-190 | 190-200 |
No. of workers | : | 5 | 10 | 20 | 9 | 6 | 2 |
Answer:
Less than Cumulative Frequency Distribution
Marks | Number of Students |
Less than 150 Less than 160 Less than 170 Less than 180 Less than 190 Less than 200 |
5 5 + 10 = 15 15 + 20=35 35 + 9 = 44 44 + 6 = 50 50 + 2 = 52 |
More than Cumulative Frequency Distribution
Marks | Number of Students |
More than 140 More than 150 More than 160 More than 170 More than 180 More than 190 |
52 52 − 5 = 47 47 − 10 = 37 37 − 20 = 17 17 − 90 = 8 8 − 6 = 2 |
Page No 73:
Question 9:
Find out the frequency distribution and 'more than' cumulative frequency table:
Price (₹) below | : | 10 | 20 | 30 | 40 | 50 | 60 |
Quantity(kg) | : | 17 | 22 | 29 | 37 | 50 | 60 |
Answer:
The frequency distribution for the given data is as follows.
Price | Class Interval | Quantity (f) |
Less than 10 Less than 20 Less than 30 Less than 40 Less than 50 Less than 60 |
0 − 10 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60 |
17 22 − 17 = 5 29 − 22 = 7 37 − 29 = 8 50 − 37 = 13 60 − 50 = 10 |
More than Cumulative Frequency Distribution
More than | Quantity (f) |
More than 0 More than 10 More than 20 More than 30 More than 40 More than 50 |
60 60 − 17 = 43 43 − 5 = 38 38 − 7 = 31 31 − 8 = 23 23 − 13 = 10 |
Page No 73:
Question 10:
If class mid-points in a frequency distribution of a group of persons are: 125, 132, 139, 146, 153, 160, 167, 174, 181 pounds, find:
(a) size of the class intervals, and
(b) the class boundaries.
Answer:
From the mid-values the class size is calculated using the following formula.
Class Size = Mid value of one class - Mid value of the preceding class
Class Size = 132 - 125 = 7
Now, the upper and lower limit for each of the class intervals is calculated as follows.
Mid Value | Class Interval |
125 132 139 146 153 160 167 174 181 |
121.5 − 128.5 128.5 − 135.5 135.5 − 142.5 142.5 − 149.5 149.5 − 156.5 156.5 − 163.5 163.5 − 170.5 170.5 − 177.5 177.5 − 184.5 |
Page No 73:
Question 11:
Prepare a continuous series from the following data:
Mid values | : | 125 | 135 | 145 | 155 | 165 |
Frequency | : | 10 | 9 | 12 | 8 | 6 |
Answer:
From the mid-values the class size is calculated using the following formula.
Class Size = Mid value of one class - Mid value of the preceding class
Class Size = 135 - 125 = 10
Now, the upper and lower limit for each of the class intervals is calculated as follows.
Mid Value | Class Interval | f |
125 135 145 155 165 |
120 − 130 130 − 140 140 − 150 150 − 160 160 − 170 |
10 9 12 8 6 |
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